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Compound (X) on reduction with LiAIH(4)...

Compound (X) on reduction with `LiAIH_(4)` gives a hydride (Y) containing 21.72% hydrogen along with other products. The compound (Y) reacts with air explosively resulting in boron trioxide. Compounds X and Y are repectively.

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Compound `X` on reduction with `LiAlH_(4)` gives a hydride `Y` containing `21.72 %` hydrogen along with other products. Compound `Y` reacts with air explosively, resulting in boron trioxide. `Y` seems to be a hydride of boron, may be `B_(2)H_(6)`. Molecular mass of hydride :
Percentage of `H` in `B_(2)H_(6) = (Mass of H)/(Mass of B_(2) H_(6)) xx 100`
=`(6)/(27.6) xx 100 = 21.73 %`
This matches the given data, so the hydride is `B_(2)H_(6)`.
`X` is some halide of boron which is reduced to `B_(2)H_(6)` with lithium aluminium hydride.
`4BX_(3)+3LiAlH_(4)to 2B_(2)H_(6) +3AlX_(3)+ 3LiX`
`B_(2)H_(6)+3O_(2) to B_(2)O_(3) + 3H_(2)O`.
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