Home
Class 11
CHEMISTRY
HgCl2 and SnCl2 cannot exist together in...

`HgCl_2` and `SnCl_2` cannot exist together in an aqeous solution . Explain.

Text Solution

AI Generated Solution

To explain why `HgCl_2` and `SnCl_2` cannot exist together in an aqueous solution, we can follow these steps: ### Step 1: Identify the Nature of the Compounds - `HgCl_2` (Mercury(II) chloride) and `SnCl_2` (Tin(II) chloride) are both ionic compounds that can dissociate in aqueous solution. ### Step 2: Understand the Reducing and Oxidizing Agents - `SnCl_2` is known to be a strong reducing agent. This means it has the ability to donate electrons and reduce other substances. ...
Promotional Banner

Topper's Solved these Questions

  • P-BLOCK GROUP 14 - CARBON FAMILY

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex (Subjective)|21 Videos

  • P-BLOCK GROUP 14 - CARBON FAMILY

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex (Objective)|19 Videos

  • P-BLOCK GROUP 14 - CARBON FAMILY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Archives (Subjective)|9 Videos

  • P-BLOCK GROUP 13 - BORON FAMILY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercise Archives (Subjecive)|9 Videos

  • PERIODIC CLASSIFICATION OF ELEMENTS AND GENERAL INORGANIC CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Archives )Subjective|4 Videos

Similar Questions

Explore conceptually related problems

Assertion: HgCl_(2) and SnCl_(2) cannot exist together in an aqueous solution. Reason: SnCl_(2) is a strong reducing agent because Sn shows inert part effect.

The following species cannot exist in an aqueous solution?

The pairs of compounds which cannot exist together in aqueous solution are

The pair of compounds which can exist together in aqueous solution is

NaHCO_(3) and NaOH cannot exist together in solution. Why ?

Which of following ions do not exist together in aqueous solution:

The pair of compounds which cannot exist together in aqueous solution is: (I) NaH_(2)PO_(4) and NaHCO_(3)" "(II) Na_(2)CO_(3) and NaHCO_(3) (III) NaOH and NaH_(2)PO_(2)" "(IV) NaHCO_(3) and NaOH

B^(3+) cannot exist in aqueous solution because of its :

The pairs of compounds which cannot exist together in aquous solution are: (I) NaH_(2)PO_(4) and Na_(2)HCO_(3) (II) Na_(2)CO_(3) and NaOH (III) NaOH and NaH_(2)PO_(4) (IV) NaHCO_(3) and NaOH

Sn^(2+) and Fe^(3+) cannot exist in the same solution.