A metal `M` forms two chlorides `M Cl_2` and `MCl_4` respectively . In which group , metal `M` can be placed ?

Explanation

To determine the group in which the metal \( M \) can be placed based on the chlorides \( MCl_2 \) and \( MCl_4 \), we can follow these steps:

### Step 1: Identify the oxidation states of the metal \( M \)
- For \( MCl_2 \):
- The oxidation state of chlorine (Cl) is \(-1\).
- Therefore, the equation can be set up as:
\[
x - 2 = 0 \quad \text{(where \( x \) is the oxidation state of \( M \))}
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