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Assertion (A) : PbI4 is a stable compou...

Assertion (A) : `PbI_4` is a stable compound .
Reason (R) : Iodide ion stablised by higher oxidation state

A

(a) If both (A) and (R) are correct and (R) is correct explanation of (A)

B

If both (A) and (R) are correct and (R) is not correct explanation of (A)

C

(c) If (A) is correct , but (R) is incorrect

D

(d) If both (A) and (R) are incorrect

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the assertion and reason provided in the question, we will break it down step by step. ### Step-by-Step Solution: 1. **Understanding the Assertion**: - The assertion states that `PbI4` (lead(IV) iodide) is a stable compound. - To evaluate this, we need to consider the oxidation states of lead in this compound. 2. **Determining the Oxidation State of Lead**: - In `PbI4`, lead (Pb) has an oxidation state of +4. - Iodine (I) has an oxidation state of -1. Since there are four iodide ions, the total contribution from iodine is -4. Thus, for the compound to be neutral, lead must be +4. 3. **Comparing Oxidation States**: - Lead can exhibit two common oxidation states: +2 and +4. - Generally, the +2 oxidation state of lead is more stable than the +4 oxidation state due to the inert pair effect. 4. **Inert Pair Effect**: - The inert pair effect refers to the tendency of the s-electrons (in this case, the 6s electrons of lead) to remain non-bonding or "inert" when forming compounds, especially in heavier elements. - This effect makes the +2 oxidation state more stable than the +4 oxidation state for lead. 5. **Conclusion on Assertion**: - Since the +4 oxidation state is less stable, `PbI4` is not a stable compound. Therefore, the assertion that `PbI4` is stable is incorrect. 6. **Understanding the Reason**: - The reason states that the iodide ion is stabilized by the higher oxidation state. - However, this is not true for larger halides like iodine. Higher oxidation states are generally stabilized in smaller and more electronegative halogens (like fluorine) but not in iodine. 7. **Conclusion on Reason**: - Since the reason is also incorrect, we conclude that both the assertion and the reason are false. 8. **Final Answer**: - Both the assertion and the reason are incorrect.

To analyze the assertion and reason provided in the question, we will break it down step by step. ### Step-by-Step Solution: 1. **Understanding the Assertion**: - The assertion states that `PbI4` (lead(IV) iodide) is a stable compound. - To evaluate this, we need to consider the oxidation states of lead in this compound. ...
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  5. Assertion (A) : Silicones are hdyreopbhobic in nature . Reason (R) ...

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  6. Assertion (A) : SnI4 is an orange solid . Reason (R) : The colur a...

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  7. Assertion (A) : Graphite is a good conductor of heat and electricity ...

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  9. Assertion (A) : Carbon forms a large number of compounds . Reason ...

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  10. Assertion (A) : Both CO2 snd SiO2 have same structure . Reason (R)...

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  11. Assertion (A) : Lead leaves a black amrek on paore Reason (R) : Le...

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  12. Assertion (A) : CO2 is linear Reason (R) : C is not in sp- hybridi...

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  13. Assertion (A) : Maximum covalency of carbon is four . Reason (R) : ...

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  14. Assertion (A) : Graphite is soft while diamond is very hard . Reaso...

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  15. Assertion (A) : Silica is soluble in HF. Reason (R) : SiO2 + 4HF ...

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  16. Assertion (A) : Graphite is chemically more reactive than diamond . ...

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  17. Assertion (A) : The compound (CF3)3 N shows almost no basic character...

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  18. Assertion (A) : When CO2 is passed through lime water the solution tu...

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  19. Assertion (A) : SnCl2 has high meling point , whereas snCl4 has low m...

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  20. Assertion (A) : C Cl4 is inert towards hydrolysis but SiCl4 is readi...

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