Assertion (A) : The compound `(CF_3)_3 N` shows almost no basic character even though `(CH_3 )_3 N` does .
Reason (R) : There is no hydrogen bonding in ` (CF_3)_3N`.

Options

A. If both (A) and (R) are correct and (R) is correct explanation of (A)
B. If both (A) and (R) are correct and (R) is not correct explanation of (A)
C. If (A) is correct , but (R) is incorrect
D. If (A) is incorrect but (R) is correct .

Explanation

To solve the question regarding the assertion and reason statements, we will analyze each part step by step.

### Step 1: Understand the Assertion
The assertion states that the compound `(CF_3)_3N` shows almost no basic character, while `(CH_3)_3N` does.

- **Basic Character**: A compound's basic character refers to its ability to donate a lone pair of electrons to accept protons (H+ ions).
- **Comparison**: We need to compare the structures of `(CF_3)_3N` and `(CH_3)_3N`.

### Step 2: Analyze the Structures
1. **Structure of `(CF_3)_3N`**:
- The nitrogen atom is bonded to three fluorine atoms.
- Fluorine is highly electronegative, which means it pulls electron density away from the nitrogen atom.
- This results in a decrease in the availability of the lone pair on nitrogen for donation.

2. **Structure of `(CH_3)_3N`**:
- The nitrogen atom is bonded to three methyl groups (CH3).
- Methyl groups are less electronegative compared to fluorine, allowing the nitrogen's lone pair to be more available for donation.

### Step 3: Determine Basic Character
- **For `(CF_3)_3N`**: The strong electronegativity of fluorine leads to a significant withdrawal of electron density from nitrogen, making the lone pair less available for donation. Therefore, it shows almost no basic character.
- **For `(CH_3)_3N`**: The electron-donating nature of the methyl groups allows the nitrogen's lone pair to be readily available for donation, resulting in a strong basic character.

### Step 4: Understand the Reason
The reason states that there is no hydrogen bonding in `(CF_3)_3N`.

- **Hydrogen Bonding**: Hydrogen bonding typically occurs when hydrogen is bonded to highly electronegative atoms (like O, N, or F). In `(CF_3)_3N`, there are no hydrogen atoms bonded to nitrogen, so hydrogen bonding cannot occur.
- However, the lack of hydrogen bonding does not directly explain the basic character of the compound. The primary reason for the low basic character is the strong electronegativity of fluorine, which withdraws electron density from nitrogen.

### Step 5: Conclusion
- **Assertion (A)**: True. `(CF_3)_3N` has almost no basic character compared to `(CH_3)_3N`.
- **Reason (R)**: True. There is no hydrogen bonding in `(CF_3)_3N`, but it does not explain the assertion correctly.

### Final Answer
Both the assertion and the reason are correct, but the reason is not the correct explanation for the assertion.

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