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Statement I: Pb^(4+) compounds are stron...

Statement I: `Pb^(4+)` compounds are stronger oxidizing agents than `Sn^(4+)` compounds.
Statement II:The higher oxidation states for the group 14 elements are more stable for the heavier members of the group due to ‘inert pair effect’.

A

If bothe (A) and ( R) are correct and (R) is correct eplanation of (A)

B

If bothe (A) and ( R) are correct and (R) is correct eplanation of (A)

C

If (A) is correct , buyt (R) is incrorect .

D

If (A) is incrorect byt ( R) is correct .

Text Solution

Verified by Experts

The correct Answer is:
C

Aswsertion (A) is true , reason (R) is false .
Down the group , the inert pair effect incerases , therefore , the higher oxidation state becomes less stabnle , and the lower oxidation state becomes more stable down the proup .`Pb^(4+)` has a higher tendency to pass into `Pb^(2+)` and is , therefore , a good oxidisng agent compared to `Sn^(4+)`.
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Assertion (A) : Pb^(+4) compounds are stronger oxidiising agents than Sn^(4+) compounds . Reason (R): The higher oxidation states for group 14 elements are more stable for the heavier members of the group due to inert pair effect .

Assertion (A) : Pb^(+4) compounds are stronger oxidiising agents than Sn^(4+) compounds . Reason (R): The higher oxidation states for group 14 elements are more stable for the heavier members of the group due to inert pair effect .

Knowledge Check

  • Assertion : Cr(VI) in the form of dichromate in acidic medium is a strong oxidising agent where MoO_3 and WO_3 are not. Reason: In d-block elements higher oxidation states are favoured by heavier members.

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    B
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    C
    If assertion is trun but reason is false.
    D
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