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A overset("Calcination")rarr CaO + MgO +...

`A overset("Calcination")rarr CaO + MgO + underset("Colourless gas")((B))`
When the colourless gas `(B)` is passed through lime water, initially a milky solution is obtained and on excess passage of gas `(B)` through the lime water, milkiness disappears.
Milkiness of lime water solution disappears due to the formation of :

A

`CaCO_(3)`

B

`Ca(HCO_(3))_(2)`

C

`Ca(OH)_(2)`

D

`CaCl_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's analyze the information provided and the chemical reactions involved. ### Step 1: Identify the reaction taking place during calcination - The question states that compound A undergoes calcination to produce calcium oxide (CaO), magnesium oxide (MgO), and a colorless gas (B). - From the context, we can deduce that compound A is likely a carbonate, specifically dolomite (CaCO3·MgCO3), which decomposes upon heating. ### Step 2: Write the balanced equation for calcination - The calcination of dolomite can be represented as: \[ \text{CaCO}_3 \cdot \text{MgCO}_3 \xrightarrow{\text{heat}} \text{CaO} + \text{MgO} + \text{CO}_2 \uparrow \] - Here, the colorless gas (B) is identified as carbon dioxide (CO2). ### Step 3: Understand the reaction of CO2 with lime water - Lime water is a saturated solution of calcium hydroxide (Ca(OH)2). When carbon dioxide is passed through lime water, it reacts to form calcium carbonate (CaCO3), which is insoluble and gives a milky appearance to the solution: \[ \text{Ca(OH)}_2 + \text{CO}_2 \rightarrow \text{CaCO}_3 \downarrow + \text{H}_2\text{O} \] ### Step 4: Analyze the effect of excess CO2 - When excess carbon dioxide is passed through the lime water, the calcium carbonate formed initially reacts with more carbon dioxide to form calcium bicarbonate (Ca(HCO3)2), which is soluble in water: \[ \text{CaCO}_3 + \text{CO}_2 + \text{H}_2\text{O} \rightarrow \text{Ca(HCO}_3)_2 \] - The formation of calcium bicarbonate leads to the disappearance of the milky solution. ### Conclusion - Therefore, the milkiness of lime water solution disappears due to the formation of calcium bicarbonate (Ca(HCO3)2). ### Final Answer The milkiness of lime water solution disappears due to the formation of calcium bicarbonate. ---

To solve the problem step by step, let's analyze the information provided and the chemical reactions involved. ### Step 1: Identify the reaction taking place during calcination - The question states that compound A undergoes calcination to produce calcium oxide (CaO), magnesium oxide (MgO), and a colorless gas (B). - From the context, we can deduce that compound A is likely a carbonate, specifically dolomite (CaCO3·MgCO3), which decomposes upon heating. ### Step 2: Write the balanced equation for calcination - The calcination of dolomite can be represented as: ...
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