Copper is the most noble of first row transition metals and occurs in small deposits in serveral countries. Ores of copper include chalcanthite `(CuSO_(4).5H_(2)O)`, atacanite `[Cu_(2)Cl(OH)_(3)]`, cuprite `(Cu_(2)O)`, copper glance `(Cu_(2)S)`, and malachite `[Cu_(2)(OH)_(2)CO_(3)]`. However, `80 %` of the world copper production comes from the ore chalcopyrite `(CuFeS_(2))`. The extraction of copper from chalcopyrite involves partial roasting, removal of iron and self-reduction.
Iron is removed from chalcopyrite as.

Options

A. `FeO`
B. `FeS`
C. `Fe_(2) O_(3)`
D. `FeSiO_(3)`

Explanation

To extract copper from chalcopyrite (CuFeS₂), the process involves several steps, including partial roasting, removal of iron, and self-reduction. Here’s a step-by-step breakdown of how iron is removed from chalcopyrite:

### Step-by-Step Solution:

1. **Understanding Chalcopyrite**:
- Chalcopyrite is a copper iron sulfide ore with the formula CuFeS₂.

2. **Partial Roasting**:
- The first step in the extraction process is partial roasting, which involves heating the chalcopyrite in the presence of oxygen. This process converts the sulfide ore into oxides.

3. **Chemical Reaction During Roasting**:
- During partial roasting, chalcopyrite is oxidized to produce cuprous sulfide (Cu₂S), ferrous sulfide (FeS), and sulfur dioxide (SO₂). The balanced chemical equation for this reaction can be represented as:
\[ 2 \text{CuFeS}_2 + 3 \text{O}_2 \rightarrow 2 \text{Cu}_2\text{S} + 2 \text{FeS} + 2 \text{SO}_2 \]

4. **Formation of Copper Oxide**:
- The cuprous sulfide (Cu₂S) formed in the previous step is then further oxidized in the presence of excess oxygen to produce cuprous oxide (Cu₂O) and more sulfur dioxide:
\[ 2 \text{Cu}_2\text{S} + 3 \text{O}_2 \rightarrow 4 \text{Cu}_2\text{O} + 2 \text{SO}_2 \]

5. **Removal of Iron**:
- The ferrous sulfide (FeS) produced in the roasting step is then reacted with oxygen to form iron(II) oxide (FeO):
\[ 4 \text{FeS} + 3 \text{O}_2 \rightarrow 4 \text{FeO} + 4 \text{SO}_2 \]

6. **Formation of Slag**:
- To remove iron from the process, iron(II) oxide (FeO) is reacted with silicon dioxide (SiO₂) to form iron silicate (FeSiO₃), which is known as slag:
\[ \text{FeO} + \text{SiO}_2 \rightarrow \text{FeSiO}_3 \]

7. **Conclusion**:
- The iron is effectively removed from chalcopyrite in the form of iron silicate (FeSiO₃), which can be separated from the copper-containing materials.

### Final Answer:
Iron is removed from chalcopyrite as iron silicate (FeSiO₃).

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