Roasting is a process in which the ore (mostly sulphide) is heated strongly in the presence of excess of air. The heating should be done at a temperature below the melting point of the ore.
`2PbS + 3O_(2) rarr A + 2SO_(2)`
The name of `A` is.

Options

A. Litharge
B. Galena
C. Sesquioxide
D. None of these

Explanation

To solve the question regarding the roasting process and the formation of compound A, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Roasting Process**:
Roasting is a method used to extract metals from their ores, particularly sulfide ores. In this process, the ore is heated in the presence of excess air (oxygen).

2. **Identify the Reaction**:
The given reaction is:
\[ 2 \text{PbS} + 3 \text{O}_2 \rightarrow A + 2 \text{SO}_2 \]
Here, PbS represents lead sulfide, and SO₂ is sulfur dioxide.

3. **Determine the Products**:
When lead sulfide (PbS) is roasted in the presence of oxygen, it reacts to form lead oxide (PbO) and sulfur dioxide (SO₂). Therefore, we need to identify what compound A is.

4. **Write the Balanced Equation**:
The balanced chemical equation for the roasting of lead sulfide is:
\[ 2 \text{PbS} + 3 \text{O}_2 \rightarrow 2 \text{PbO} + 2 \text{SO}_2 \]
From this equation, we can see that A is lead oxide (PbO).

5. **Name of Compound A**:
The compound A, which is formed during the roasting of lead sulfide, is lead oxide.

### Final Answer:
The name of A is **lead oxide (PbO)**.

---