In the process of extraction of gold,
Roasted gold ore `+CN^(-)+H_2Ooverset(o_2)rarr[X]+OH^(-)`
`[X]+Znrarr[Y]+Au`
Identify the complexes [X] and [Y]

Options

A. `X =[Au(CN)_(2)]^(Ө), Y = [Zn(CN)_(4)]^(2-)`
B. `X =[Au(CN)_(2)]^(3-), Y =[Zn(CN)_(4)]^(2-)`
C. `X =[Au(CN)_(2)]^(Ө), Y =[Zn(CN)_(6)]^(4-)`
D. `X =[Au(CN)_(4)]^(Ө), Y [Zn(CN)_(4)]^(2-)`

Explanation

To solve the problem of identifying the complexes [X] and [Y] in the extraction of gold process, we will analyze the given reactions step by step.

### Step 1: Analyze the first reaction
The first reaction provided is:
\[ \text{Roasted gold ore} + \text{CN}^- + \text{H}_2\text{O} \overset{\text{O}_2}{\rightarrow} [X] + \text{OH}^- \]

In this reaction, roasted gold ore is treated with cyanide ions (CN^-) in the presence of water and oxygen. The cyanide ions form a complex with gold.

### Step 2: Determine the complex [X]
The complex formed in the first reaction is a cyanide complex of gold. The cyanide ion has a charge of -1, and since two cyanide ions coordinate with one gold atom, we can write the complex as:
\[ [X] = \text{Au(CN)}_2^- \]

### Step 3: Analyze the second reaction
The second reaction is:
\[ [X] + \text{Zn} \rightarrow [Y] + \text{Au} \]

Here, the complex [X] reacts with zinc (Zn). Zinc will displace the gold from the complex.

### Step 4: Determine the complex [Y]
When zinc reacts with the complex [X], it forms another complex. The zinc ion can coordinate with four cyanide ions, leading to the formation of:
\[ [Y] = \text{Zn(CN)}_4^{2-} \]

### Conclusion
Thus, the complexes identified are:
- [X] = Au(CN)₂⁻
- [Y] = Zn(CN)₄²⁻

### Final Answer
- [X] = Au(CN)₂⁻
- [Y] = Zn(CN)₄²⁻

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