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Explain the following : An acidified K...

Explain the following :
An acidified `K_2 Cr_2 O_7` paper turns green when exposed to `SO_2`.

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AI Generated Solution

To explain why an acidified \( K_2Cr_2O_7 \) paper turns green when exposed to \( SO_2 \), we can break down the process into several steps: ### Step 1: Understanding the Reactants - **Potassium Dichromate**: \( K_2Cr_2O_7 \) is a strong oxidizing agent that is orange in color due to the presence of chromium in the +6 oxidation state. - **Sulfur Dioxide**: \( SO_2 \) is a reducing agent. ### Step 2: The Reaction - When \( SO_2 \) gas comes into contact with acidified \( K_2Cr_2O_7 \), a redox reaction occurs. The sulfur dioxide reduces the chromium from +6 to +3 oxidation state. ...
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