`H_2 SO_4` is the most important acid used in the chemical industry. Concentrated `H_2 SO_4` has quite strong oxidising properties.
Oxidation state of `S` in `H_2 SO_4` is

Options

A. `+6`
B. `+ 4`
C. `+ 2`
D. `+ 3`

Explanation

To find the oxidation state of sulfur (S) in sulfuric acid (H₂SO₄), we can follow these steps:

### Step 1: Assign Variables
Let the oxidation state of sulfur be represented as \( X \).

### Step 2: Write the Equation
In H₂SO₄, we have:
- 2 hydrogen atoms (H) each with an oxidation state of +1.
- 4 oxygen atoms (O) each with an oxidation state of -2.

The overall charge of the molecule is neutral (0). Therefore, we can set up the equation:
\[ X + 2(+1) + 4(-2) = 0 \]

### Step 3: Simplify the Equation
Now, simplify the equation:
\[ X + 2 - 8 = 0 \]
\[ X - 6 = 0 \]

### Step 4: Solve for X
Now, solve for \( X \):
\[ X = +6 \]

### Conclusion
The oxidation state of sulfur in H₂SO₄ is +6.

### Final Answer
Thus, the oxidation state of sulfur (S) in sulfuric acid (H₂SO₄) is **+6**.

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