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Oxygen has - 2 oxidation state in the co...

Oxygen has `- 2` oxidation state in the compound

A

`MgO`

B

`F_2 O`

C

`Na_2 O`

D

`H_2 O_2`

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The correct Answer is:
To determine the oxidation state of oxygen in various compounds and identify those where oxygen has a -2 oxidation state, we can follow these steps: ### Step 1: Analyze the first compound, MgO - **Identify the oxidation state of magnesium (Mg)**: Magnesium is in Group 2 of the periodic table and typically has a +2 oxidation state. - **Set up the equation**: Let the oxidation state of oxygen be \( X \). The overall charge of the compound is zero, so: \[ +2 + X = 0 \] - **Solve for \( X \)**: \[ X = -2 \] - **Conclusion**: In MgO, oxygen has a -2 oxidation state. ### Step 2: Analyze the second compound, F2O - **Identify the oxidation state of fluorine (F)**: Fluorine is the most electronegative element and has a -1 oxidation state. - **Set up the equation**: Let the oxidation state of oxygen be \( X \): \[ -1 \times 2 + X = 0 \] - **Solve for \( X \)**: \[ -2 + X = 0 \implies X = +2 \] - **Conclusion**: In F2O, oxygen has a +2 oxidation state. ### Step 3: Analyze the third compound, Na2O - **Identify the oxidation state of sodium (Na)**: Sodium is in Group 1 and has a +1 oxidation state. - **Set up the equation**: Let the oxidation state of oxygen be \( X \): \[ +1 \times 2 + X = 0 \] - **Solve for \( X \)**: \[ +2 + X = 0 \implies X = -2 \] - **Conclusion**: In Na2O, oxygen has a -2 oxidation state. ### Step 4: Analyze the fourth compound, H2O2 - **Identify the oxidation state of hydrogen (H)**: Hydrogen typically has a +1 oxidation state. - **Set up the equation**: Let the oxidation state of oxygen be \( X \): \[ +1 \times 2 + X \times 2 = 0 \] - **Solve for \( X \)**: \[ +2 + 2X = 0 \implies 2X = -2 \implies X = -1 \] - **Conclusion**: In H2O2, oxygen has a -1 oxidation state. ### Final Conclusion From the analysis: - In **MgO**, oxygen has a -2 oxidation state. - In **Na2O**, oxygen also has a -2 oxidation state. - In **F2O**, oxygen has a +2 oxidation state. - In **H2O2**, oxygen has a -1 oxidation state. Thus, the compounds where oxygen has a -2 oxidation state are **MgO** and **Na2O**.
To determine the oxidation state of oxygen in various compounds and identify those where oxygen has a -2 oxidation state, we can follow these steps: ### Step 1: Analyze the first compound, MgO - **Identify the oxidation state of magnesium (Mg)**: Magnesium is in Group 2 of the periodic table and typically has a +2 oxidation state. - **Set up the equation**: Let the oxidation state of oxygen be \( X \). The overall charge of the compound is zero, so: \[ +2 + X = 0 \] ...
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