When oxygen is passed through a solution of `Na_2 SO_3`, we get

Options

A. `Na_2 S`
B. `Na_2 SO_4`
C. `NaHSO_4`
D. `NaH`

Explanation

To solve the question, "When oxygen is passed through a solution of Na2SO3, we get," we need to analyze the chemical reaction that occurs when oxygen interacts with sodium sulfite (Na2SO3).

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are sodium sulfite (Na2SO3) and oxygen (O2).

2. **Write the Reaction**: When oxygen is passed through a solution of sodium sulfite, the reaction can be represented as follows:
\[ \text{Na}_2\text{SO}_3 + \text{O}_2 \rightarrow \text{Na}_2\text{SO}_4 \]
Here, sodium sulfite is oxidized to sodium sulfate (Na2SO4).

3. **Balancing the Reaction**: To ensure that the reaction is balanced, we need to check the number of atoms of each element on both sides of the equation.
- On the left side, we have:
- Sodium (Na): 2
- Sulfur (S): 1
- Oxygen (O): 3 from Na2SO3 + 2 from O2 = 5
- On the right side, in sodium sulfate (Na2SO4):
- Sodium (Na): 2
- Sulfur (S): 1
- Oxygen (O): 4 from Na2SO4

To balance the oxygen atoms, we can adjust the equation:
\[ 2 \text{Na}_2\text{SO}_3 + \text{O}_2 \rightarrow 2 \text{Na}_2\text{SO}_4 \]
This gives us:
- Left side: 4 Na, 2 S, 8 O
- Right side: 4 Na, 2 S, 8 O

The equation is now balanced.

4. **Conclusion**: The product formed when oxygen is passed through a solution of sodium sulfite is sodium sulfate (Na2SO4).

### Final Answer:
When oxygen is passed through a solution of Na2SO3, we get sodium sulfate (Na2SO4).