Aqueous solution of `Na_(2)S_(2)O_(3)` on reaction with `CI_(2)`, gives

Options

A. `Na_(2)S_(4)O_(6)`
B. `NaHSO_(4)`
C. `HCI`
D. `NaOH`

Explanation

To solve the problem of what happens when an aqueous solution of \( \text{Na}_2\text{S}_2\text{O}_3 \) (sodium thiosulfate) reacts with \( \text{Cl}_2 \) (chlorine gas), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Sodium thiosulfate: \( \text{Na}_2\text{S}_2\text{O}_3 \)
- Chlorine gas: \( \text{Cl}_2 \)

### Step 2: Understand the Reaction
Sodium thiosulfate acts as a reducing agent and can be oxidized by chlorine. The chlorine gas will oxidize the thiosulfate ion.

### Step 3: Write the Balanced Chemical Equation
When sodium thiosulfate reacts with chlorine, the products formed are sodium hydrogen sulfate and hydrochloric acid. The balanced chemical equation for this reaction is:

\[ \text{Na}_2\text{S}_2\text{O}_3 + \text{Cl}_2 + \text{H}_2\text{O} \rightarrow \text{NaHSO}_4 + 2 \text{HCl} + \text{NaCl} \]

### Step 4: Identify the Products
From the balanced equation, we can see that the products of the reaction are:
- Sodium hydrogen sulfate: \( \text{NaHSO}_4 \)
- Hydrochloric acid: \( \text{HCl} \)

### Step 5: Conclusion
Thus, the reaction of an aqueous solution of \( \text{Na}_2\text{S}_2\text{O}_3 \) with \( \text{Cl}_2 \) produces sodium hydrogen sulfate and hydrochloric acid.

### Final Answer
The products are \( \text{NaHSO}_4 \) and \( \text{HCl} \).

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