Bromine can be liberated form potassium bromide solution by the action of

Options

A. Iodine solutoin
B. Chlorine water
C. Sodium chloride
D. Potassium iodide

Explanation

To solve the question "Bromine can be liberated from potassium bromide solution by the action of?", we need to analyze the options provided and understand the concept of oxidation and reduction in the context of halogens.

### Step-by-Step Solution:

1. **Identify the Oxidation States**:
- In potassium bromide (KBr), bromine (Br) is in the oxidation state of -1.
- When bromine is liberated, it is in the oxidation state of 0 (Br2).

2. **Determine the Process**:
- To liberate bromine from KBr, bromine must undergo oxidation (from -1 to 0). Therefore, we need an oxidizing agent that can oxidize bromine.

3. **Assess the Oxidizing Power of Halogens**:
- The oxidizing power of halogens decreases in the order: Chlorine (Cl2) > Bromine (Br2) > Iodine (I2).
- This means chlorine is a stronger oxidizing agent than bromine, while iodine is a weaker oxidizing agent.

4. **Evaluate the Options**:
- **Iodine solution**: Iodine has less oxidizing power than bromine, so it cannot oxidize bromine.
- **Chlorine solution**: Chlorine has more oxidizing power than bromine, so it can oxidize bromine from KBr.
- **Sodium Fluoride (NaF)**: Sodium fluoride does not contain a halogen that can oxidize bromine.
- **Potassium Iodide (KI)**: Iodine in potassium iodide cannot oxidize bromine because it has less oxidizing power.

5. **Conclusion**:
- The only option that can liberate bromine from potassium bromide solution is **Chlorine solution**.

### Final Answer:
Bromine can be liberated from potassium bromide solution by the action of **Chlorine solution**.

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