What are the products formed in the reaction of xenon hexafluoride with silicon dioxide?

Options

A. `XeSiO_(4) + HF`
B. `XeF_(2) + SiF_(4)`
C. `XeOF_(4) + SiF_(4)`
D. `XeO_(3) + SiF_(2)`

Explanation

To determine the products formed in the reaction of xenon hexafluoride (XeF6) with silicon dioxide (SiO2), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Xenon hexafluoride (XeF6)
- Silicon dioxide (SiO2)

### Step 2: Understand the Reaction Mechanism
In the reaction, xenon hexafluoride (XeF6) interacts with silicon dioxide (SiO2). The silicon dioxide provides oxygen, which will bond with xenon, while the fluorine from xenon hexafluoride will bond with silicon.

### Step 3: Write the Reaction
The reaction can be represented as follows:
\[ \text{XeF}_6 + \text{SiO}_2 \rightarrow \text{XeOF}_4 + \text{SiF}_4 \]

### Step 4: Balance the Reaction
To balance the reaction, we observe that:
- 2 molecules of XeF6 will react with 1 molecule of SiO2 to produce 2 molecules of XeOF4 and 1 molecule of SiF4. Therefore, the balanced equation is:
\[ 2 \text{XeF}_6 + \text{SiO}_2 \rightarrow 2 \text{XeOF}_4 + \text{SiF}_4 \]

### Step 5: Identify the Products
From the balanced equation, we can identify the products formed:
- Xenon oxytetrafluoride (XeOF4)
- Silicon tetrafluoride (SiF4)

### Final Answer
The products formed in the reaction of xenon hexafluoride with silicon dioxide are:
- Xenon oxytetrafluoride (XeOF4)
- Silicon tetrafluoride (SiF4)

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