How many dpi-per bonds are there in `XeO_(4)`?

Explanation

To determine the number of dπ-pπ bonds in \( \text{XeO}_4 \), we can follow these steps:

### Step 1: Determine the Structure of \( \text{XeO}_4 \)
- Xenon (Xe) is the central atom surrounded by four oxygen (O) atoms.
- Each oxygen atom forms a double bond with xenon.

### Step 2: Identify the Hybridization of Xenon
- In \( \text{XeO}_4 \), xenon undergoes sp³ hybridization. This is because it forms four sigma bonds with the four oxygen atoms.

### Step 3: Understand the Bonding in \( \text{XeO}_4 \)
- Each double bond between xenon and oxygen consists of one sigma (σ) bond and one pi (π) bond.
- The π bonds are formed from the p orbitals of oxygen overlapping with the d orbitals of xenon.

### Step 4: Count the dπ-pπ Bonds
- Since there are four double bonds (one for each oxygen), and each double bond includes one dπ-pπ bond, we can conclude that there are four dπ-pπ bonds in \( \text{XeO}_4 \).

### Final Answer
- Therefore, the number of dπ-pπ bonds in \( \text{XeO}_4 \) is **4**.

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