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(a). An ore (A) on roasting with sodium ...

(a). An ore (A) on roasting with sodium carbonate and lime in the presence of air gives two compounds (B) and (C).
(b). The solution of (B) in conc. HCl on treatment with potassiu ferroyanide gives a blue colour or precipitate of compound (D).

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To solve the given question step by step, we will break it down into parts (a) and (b) as described. ### Step-by-Step Solution: **(a)** Identify the ore (A) and the reaction with sodium carbonate and lime. 1. **Identify the Ore (A)**: The ore mentioned is likely to be chromite, which has the formula \( \text{FeOCr}_2\text{O}_3 \). ...
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(i)A blue coloured compound (A) on heating gives two product (B) & ( C) . (ii)A metal (D) is deposited on passing hydrogen through heated (B) . (iii)The solution of (B) in HCl on treatment with the [Fe(CN)_(6)]^(4-) gives a chocolate brown coloured precipitate of compound (E) . (iv) (C ) turns lime water milky which disappears on continuous passage of (C ) forming a compound (F) . Identigfy (A) to (F) and give chemical equations for the reactions at step (i) to (iv).

(i) A powdered substance (A) on treatment with fusion mixture gives a green coloured compound (B). (ii) The solution of (B) in boiling water on acidification with dilute H_(2)SO_(4) gives a pink coloured compound (C ) . (iii) The aqueous solution of (A) on treatment with NaOH and Br_(2)- water gives a compound (D). (iv) A solution of (D) in conc. HNO_(3) on treatment with lead peroxide at boiling temperature produced a compound (E) which was of the same color at that of (C). (v) A solution of (A) on treatment with a solution of barium chloride gave a white precipitate of compound (F) Which was insoluble in conc. HNO_(3) and conc. HCl. Consider the following statement : (I) Anions of both (B) and (C ) are diamagnetic and have tetradhedral geometray. (II) Anions of both (B) and ( C) are paramagnetic and have tetrahedral geometry. (III) Anions of (B) is paramagnetic and that of (C ) is diamagnetic but both have same tetrahedral geometry. (IV) Green coloured compound (B) in a neutral of acidic medium disproportionates to give (C ) and (D). Of these select the correct one from the code given :

(i) A powdered substance (A) on treatment with fusion mixture gives a green coloured compound (B). (ii) The solution of (B) in boiling water on acidification with dilute H_(2)SO_(4) gives a pink coloured compound (C ) . (iii) The aqueous solution of (A) on treatment with NaOH and Br_(2)- water gives a compound (D). (iv) A solution of (D) in conc. HNO_(3) on treatment with lead peroxide at boiling temperature produced a compound (E) which was of the same colour at that of (C) . Identify A , B ,C ,D , E

(a). A powdered substance (A) on treatment with fusion mixture gives a green coloured compound (B). (b). The solution of (B) The solution of (B) in boiling water on acidification with dilute H_2SO_4 gives a pink coloured compound (C).

(i)A powdered substance (A) on treatment with fusion mixture (Na_2CO_3+KNO_3) gives a green coloured compound (B). (ii)The solution of (B) in boiling water on acidification with dilute H_2SO_4 gives a pink coloured compound ( C). (iii)The aqueous solution of (A) on treatment with excess of NaOH and Bromine water gives a compound (D) (iv)A solution of (D) in conc. HNO_3 on treatment with PbO_2 at boiling temperature produced a compound (E) which was of the same colour at that of (C ). Sum of oxidation number of central atom of A,B,C,D & E is:

Identify A to E. Pyrolusite on heating with KOH in the presence of air gives a dark green compound (A). The solution of (A) on treatment with H_2SO_4 gives a purple coloured compound (B) , which gives the following reactions: (a). KI on reaction with alkaline solution of (B) changes into a compound (C). (b). The colour of the compoud (B) disappears on treatment with the acidic solution of FeSO_4 . (c). With conc. H_2SO_4 compound (B) gives (D) which can compose to yield (E) and oxygen.

(i) A powdered substance (A) on treatment with fusion mixture gives a green coloured compound (B). (ii) The solution of (B) in boiling water on acidification with dilute H_(2)SO_(4) gives a pink coloured compound (C ) . The oxidation state of central metal ions of (A), (B) and (C ) compounds are respectively :

A black mineral (A) on heating in presence of air gives a gas (B). The mineral (A) on reaction with dilute H_(2)SO_(4) gives a gas (C) and a solution of a compound (D) on passing the gas (C) into an aqueous solution of (B), a white turbidity is obtained. The aqueous solution of (D) on reaction with potassium ferricyanide gives a blue compound (E). Identify (A) to (E) and give chemical equations for the reaction involved.

(a) When a chromite ore (A) is fused with an aqueous solution of sodium carbonate in free excess of air, a yellow solution of compound (B) is obtained. This solution is filtered and acidified with sulphuric acid to form compound (C). Compound (C) on treatment with solution of KCl gives orange crystals of compound (D). Write the chemical formulae of compounds A to D. (b) Describe the cause of the following variations with respect to lanthanoids and actinoids: (i) Greater range of oxidation states of actinoids as compared to lanthanoids. (ii) Greater actinoid contraction as compared to lanthanoid contraction. (iii) Lower ionisation enthalpy of early actinoids as compared to the early lanthanoids.

When a chromite ore (A) is fused with sodium carbonate in free excess of air and the product is dissolved in water, a yellow solution of compound (B) is obtained. After treatment of this yellow solution with sulphuric acid, compound (C ) can be crystallised from the solution. When compound (C ) is treated with KCl, orange crystals of compound (D) crystallise out. Identify A to D and also explain the reactions.

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