If instead of `H_2SO_4`, `HCl` or `HNO_3` of suitable concentration were used, the volume of `KMnO_4` solution used would have been

Options

A. less in case of HCl but more in case of `HNO_3`
B. More in case of HCl but less in case of `HNO_3`
C. more in both cases
D. Less in both cases

Explanation

To solve the question regarding the effect of using HCl or HNO3 instead of H2SO4 in a reaction involving KMnO4, we will analyze the behavior of KMnO4 in acidic conditions provided by these acids.

### Step-by-Step Solution:

1. **Understanding the Role of KMnO4**:
- KMnO4 is a strong oxidizing agent, and its behavior in acidic solutions is crucial to understanding how much of it will be consumed in a reaction.

2. **Effect of H2SO4**:
- When KMnO4 is used in the presence of H2SO4, it oxidizes the reductant (which could be a substance like Fe2+, C2O4^2-, etc.) effectively without any interference.

3. **Using HCl**:
- If HCl is used instead of H2SO4, the KMnO4 will still oxidize the reductant, but some of the oxygen produced from the KMnO4 will also react with HCl to form Cl2 gas. This means that more KMnO4 will be required to provide enough oxygen to oxidize both the reductant and the HCl.
- Therefore, the volume of KMnO4 used will be **more** when HCl is used.

4. **Using HNO3**:
- HNO3 is a strong oxidizing agent itself. When it is used in the reaction, it can oxidize the reductant more effectively than KMnO4 can. As a result, less KMnO4 will be needed because HNO3 will take up some of the oxidizing role.
- Thus, the volume of KMnO4 used will be **less** when HNO3 is used.

5. **Conclusion**:
- From the analysis, we can conclude:
- The volume of KMnO4 will be **more** when HCl is used.
- The volume of KMnO4 will be **less** when HNO3 is used.

### Final Answer:
The correct option is that the volume of KMnO4 solution used would be **more in case of HCl and less in case of HNO3**.

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