Photography is based on the nature of silver halides. Except AgF, the silver halides are photosensitive. These undergo decomposition in light and turn black due to formation of free silver.
`2AgBroverset(light)to2Ag+Br_2`
The photography films are prepared by adding `20%` aqueous solution of `AgNO_3` to `NH_4Br` solution containing gelatic. When such a film is exposed, emulsion gets affected and a latent image is formed on the film.
When this exposed film or plate is dipped ina developer which contains a reducing agent, the part affected most during exposure are reduced to the maximum. The image becomes visible. It is called a negative. The remaining sensitive emulsion on the negative is removed by dissolving it in hypo solution (fixer). Fihnally, a positive of the nagative already prepared is made on silver bromide paper.
Q. Silver bromide dissolves in hypo solution forming:

Options

A. `Ag_2S_2O_3`
B. `Ag_2S`
C. `Na_3[Ag(SO_3)_2)]`
D. `NaAgS_2O_3`

Answer

To solve the question regarding what silver bromide (AgBr) forms when it dissolves in hypo solution, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Components**:
- Silver bromide (AgBr) is a silver halide that is photosensitive and used in photography.
- Hypo solution, commonly known as fixer, typically contains sodium thiosulfate (Na2S2O3) as the active ingredient.

2. **Reaction of Silver Bromide with Hypo Solution**:
- When AgBr is treated with hypo solution (sodium thiosulfate), a chemical reaction occurs.
- The sodium thiosulfate acts as a reducing agent and reacts with the silver bromide.

3. **Writing the Reaction**:
- The reaction can be represented as follows:
\[ \text{Na}_2\text{S}_2\text{O}_3 + \text{AgBr} \rightarrow \text{Na}_3\text{Ag(S}_2\text{O}_3)_2 + \text{NaBr} \]
- This indicates that silver bromide reacts with sodium thiosulfate to form a complex compound along with sodium bromide.

4. **Identifying the Product**:
- The complex formed is known as sodium thiosulfate silver complex, which can be represented as:
\[ \text{Na}_3\text{Ag(S}_2\text{O}_3)_2 \]
- This complex is soluble in the hypo solution, allowing the silver bromide to dissolve.

5. **Conclusion**:
- Therefore, when silver bromide dissolves in hypo solution, it forms a soluble complex, specifically sodium thiosulfate silver complex, along with sodium bromide.

### Final Answer:
Silver bromide dissolves in hypo solution forming sodium thiosulfate silver complex (Na3Ag(S2O3)2) and sodium bromide (NaBr).

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