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What will be the correct representation of quatum numbers f the last electron entered into Ce?

A

`n=4,l=3,m=-3,s=(-1)/(2)`

B

`n=4,l=3,m=0,s=(-1)/(2)`

C

`n=4,l=2,m=-3,s(+1)/(2)`

D

`n=4,l=3,m=+2,s=(-1)/(2)`

Text Solution

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The correct Answer is:
To determine the quantum numbers of the last electron entered into cerium (Ce), we need to follow these steps: ### Step 1: Identify the Atomic Number Cerium has an atomic number of 58. This means it has 58 electrons. ### Step 2: Determine the Electron Configuration The electron configuration of cerium can be written as: \[ \text{Ce: } [Xe] 6s^2 4f^1 5d^1 \] This indicates that cerium has: - 2 electrons in the 6s subshell - 1 electron in the 4f subshell - 1 electron in the 5d subshell ### Step 3: Identify the Last Electron The last electron that enters cerium is in the 4f subshell. Therefore, we need to focus on the quantum numbers for the 4f electron. ### Step 4: Assign the Principal Quantum Number (n) The principal quantum number (n) indicates the energy level of the electron. For the 4f subshell: \[ n = 4 \] ### Step 5: Assign the Azimuthal Quantum Number (l) The azimuthal quantum number (l) describes the subshell type: - For s subshell, l = 0 - For p subshell, l = 1 - For d subshell, l = 2 - For f subshell, l = 3 Since we are dealing with the f subshell: \[ l = 3 \] ### Step 6: Assign the Magnetic Quantum Number (m_l) The magnetic quantum number (m_l) can take values from -l to +l. For f subshell (l = 3): \[ m_l = -3, -2, -1, 0, +1, +2, +3 \] Since there is only one electron in the 4f subshell, we can choose: \[ m_l = -3 \] ### Step 7: Assign the Spin Quantum Number (m_s) The spin quantum number (m_s) can be either +1/2 or -1/2. We can assign: \[ m_s = -\frac{1}{2} \] (for example, but it could also be +1/2 depending on the electron's spin direction) ### Final Representation of Quantum Numbers Thus, the quantum numbers for the last electron in cerium (4f electron) are: - \( n = 4 \) - \( l = 3 \) - \( m_l = -3 \) - \( m_s = -\frac{1}{2} \) ### Summary of Quantum Numbers The correct representation of the quantum numbers for the last electron entered into Ce is: \[ (n, l, m_l, m_s) = (4, 3, -3, -\frac{1}{2}) \] ---

To determine the quantum numbers of the last electron entered into cerium (Ce), we need to follow these steps: ### Step 1: Identify the Atomic Number Cerium has an atomic number of 58. This means it has 58 electrons. ### Step 2: Determine the Electron Configuration The electron configuration of cerium can be written as: \[ \text{Ce: } [Xe] 6s^2 4f^1 5d^1 \] ...
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