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Which of the following compound is not c...

Which of the following compound is not cooured?

A

Copper (II) sulphat

B

Zinc(II) chloride

C

Chromium(II) sulphate

D

Manganese(II oxalate)

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given compounds is not colored, we need to analyze the electronic configurations of the metal ions in each compound. A compound is typically colored if it contains unpaired electrons in its d-orbitals. Let's evaluate the compounds step by step. ### Step 1: Analyze Copper Sulfate (CuSO₄) - **Copper Ion (Cu²⁺)**: The electronic configuration of Cu is [Ar] 3d¹⁰ 4s¹. When it loses two electrons to form Cu²⁺, the configuration becomes [Ar] 3d⁹. - **Unpaired Electrons**: Cu²⁺ has one unpaired electron in the 3d orbital (3d⁹). - **Color**: Since it has unpaired electrons, CuSO₄ is colored. ### Step 2: Analyze Zinc Chloride (ZnCl₂) - **Zinc Ion (Zn²⁺)**: The electronic configuration of Zn is [Ar] 3d¹⁰ 4s². When it loses two electrons to form Zn²⁺, the configuration becomes [Ar] 3d¹⁰. - **Unpaired Electrons**: Zn²⁺ has no unpaired electrons (3d¹⁰). - **Color**: Since it has no unpaired electrons, ZnCl₂ is not colored. ### Step 3: Analyze Chromium Sulfate (Cr₂(SO₄)₃) - **Chromium Ion (Cr³⁺)**: The electronic configuration of Cr is [Ar] 3d⁵ 4s¹. When it loses three electrons to form Cr³⁺, the configuration becomes [Ar] 3d³. - **Unpaired Electrons**: Cr³⁺ has three unpaired electrons in the 3d orbital (3d³). - **Color**: Since it has unpaired electrons, Cr₂(SO₄)₃ is colored. ### Step 4: Analyze Manganese(II) Sulfate (MnSO₄) - **Manganese Ion (Mn²⁺)**: The electronic configuration of Mn is [Ar] 3d⁵ 4s². When it loses two electrons to form Mn²⁺, the configuration becomes [Ar] 3d⁵. - **Unpaired Electrons**: Mn²⁺ has five unpaired electrons in the 3d orbital (3d⁵). - **Color**: Since it has unpaired electrons, MnSO₄ is colored. ### Conclusion Among the compounds analyzed, **Zinc Chloride (ZnCl₂)** is the only compound that is not colored because it has a completely filled d-orbital with no unpaired electrons. ### Summary - **Colored Compounds**: Copper Sulfate (CuSO₄), Chromium Sulfate (Cr₂(SO₄)₃), Manganese(II) Sulfate (MnSO₄). - **Not Colored Compound**: Zinc Chloride (ZnCl₂).

To determine which of the given compounds is not colored, we need to analyze the electronic configurations of the metal ions in each compound. A compound is typically colored if it contains unpaired electrons in its d-orbitals. Let's evaluate the compounds step by step. ### Step 1: Analyze Copper Sulfate (CuSO₄) - **Copper Ion (Cu²⁺)**: The electronic configuration of Cu is [Ar] 3d¹⁰ 4s¹. When it loses two electrons to form Cu²⁺, the configuration becomes [Ar] 3d⁹. - **Unpaired Electrons**: Cu²⁺ has one unpaired electron in the 3d orbital (3d⁹). - **Color**: Since it has unpaired electrons, CuSO₄ is colored. ### Step 2: Analyze Zinc Chloride (ZnCl₂) ...
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