Mercury (I) chloride sublimes when its compound Is heated and the vapours it gives off are cooled the substance collected consists of

Options

A. Mercury (II) chloride
B. Mercury (I) and mercury (II) chlorides
C. Mercury (II) chloride andmercury
D. mercury

Explanation

To solve the question regarding the sublimation of mercury (I) chloride when heated, we can break it down into a series of logical steps:

### Step 1: Understanding Sublimation
Sublimation is the process where a solid turns directly into a gas without passing through the liquid phase. In this case, we are dealing with mercury (I) chloride, which is a solid at room temperature.

**Hint:** Remember that sublimation involves a direct transition from solid to gas.

### Step 2: Heating Mercury (I) Chloride
When mercury (I) chloride (Hg2Cl2) is heated, it sublimes. This means that it will convert into gaseous form. The reaction can be represented as:
\[ \text{Hg}_2\text{Cl}_2 (s) \rightarrow 2 \text{Hg} (g) + \text{HgCl}_2 (g) \]

**Hint:** Focus on the products formed during the sublimation process.

### Step 3: Cooling the Vapors
As the vapors of mercury (I) chloride cool down, they will condense back into solid form. The cooling process allows the gaseous products to return to a solid state.

**Hint:** Consider what happens to gases when they lose heat.

### Step 4: Analyzing the Collected Substance
The vapors that condense will consist of both mercury (Hg) and mercury (II) chloride (HgCl2). Therefore, the substance collected after cooling will contain:
- Mercury (Hg)
- Mercury (II) chloride (HgCl2)

**Hint:** Think about the components that result from the sublimation reaction.

### Step 5: Conclusion
Based on the analysis, the correct answer to the question is that the substance collected consists of both mercury and mercury (II) chloride.

**Final Answer:** The substance collected consists of mercury and mercury (II) chloride.