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KMnO4 can be prepared fromK2MnO4 as per ...

`KMnO_4` can be prepared from`K_2MnO_4` as per the reaction:
The reaction can go the completion by removing `OH^(ɵ)` ions by adding.

A

`CO_2`

B

`SO_2`

C

`HCl`

D

`KOH`

Text Solution

Verified by Experts

The correct Answer is:
A
The `overset(ɵ)(O)H` can be removed by adding HCl or `CO_2` since `MnO_4^(ɵ)` is formed in the product, which will oxidise `HCl` or `Cl^(ɵ)` ion to `Cl_2` hence `HCl` will not react with `overset(ɵ)(O)H` ions Therefore `CO_2` is used to remove `overset(ɵ)(O)H` ions.
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