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From the experimental facts given below ...

From the experimental facts given below determine the correct structure of solid `CrCI_(3) .6H_(2)O` Solution containing `0.2665g` of `CrCI_(3)6H_(2)` O was passed throuhg cation exchange resin in acid form The acid liberated was found to react completely with `30mL` of `0.10M` Na OH `("Molecular mass of" CrCI_(3).6H_(2)O=266.5)` .

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To determine the correct structure of solid `CrCl3.6H2O`, we will follow these steps: ### Step 1: Calculate the moles of `CrCl3.6H2O` We start by calculating the number of moles of `CrCl3.6H2O` using the formula: \[ \text{Moles} = \frac{\text{Given mass}}{\text{Molecular mass}} \] ...
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A solution containing 2.665 g of Cr Cl_(3).6H_(2)O is passed through a cation exchanger. The chloride ions obtained in solution react with AgNO_(3) and give 2.87 g of AgCI. Determine the structure of the compound.

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When any solution passess through a cation exchange resin that is in acidic form, H ion of the resin is replaced by cations of the solution. A solution containing 0.319 g of an isomer with molecular formula CrCl_(3).6H_(2)O is passed through a cation exchange resin in acidic form. The eluted solution requires 19 cm^(3) fo 0.125 N NaOH. The isomer is

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Which of the following is most likely structrure of CrCI_(3).6H_(2)O if 1//3 of total chlorine of the compound is precipitated by adding AgNO_(3) to its aqueous solution?

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