Megnetic moment value of `Fe(H_(2)O)_(5)(NO)]^(2+)` ion in `3.89B.M` Find the out the oxidation state of iron and type of hybridisation .

Explanation

`nu_(s)=3.89BM` corresponds to `n=3`
Thake `3.89~~4implies sqrt16 ~~ sqrt15 B.M`
The value `sqrt15 BM` corresponds to `n=3`
The oxidation state Fe in the complex
`[Fe^(+1)(H_(2)O)_(5)overset(+1)NO]^(2+)` is `+1` and `CN of Fe^(o+) =6`
`Fe(Z = 26)implies 3d^(6) 4s^(2), Fe^(o+) = 3d^(6) 4s^(1)`

Since `NO^(-+)` is a strong ligand and `H_(2)O` is a weak ligand so only one pairing of `3d` and `4s` electrons occurs which also corresponds `n =3`
(i) Oxidation state of `Fe =+1`
(ii) Hybridisation `=sp^(3) d^(2)`
(iii) Geometry = octahedral
(iv) Outer orbital complex .