For the complex `[Cr(H_(2)O)_(6)]^(2+)` calculate the total pairing energey in high spin and low spin state Given the mean pairing energey `=23500cm^(-1)` .

Explanation

To solve the problem of calculating the total pairing energy in the high spin and low spin states for the complex \([Cr(H_2O)_6]^{2+}\), we will follow these steps:

### Step 1: Determine the oxidation state of chromium
The complex is \([Cr(H_2O)_6]^{2+}\). Since water is a neutral ligand, the oxidation state of chromium can be calculated as follows:

Let the oxidation state of chromium be \(x\). The equation becomes:
\[
x + 0 = +2 \quad \text{(since the overall charge of the complex is +2)}
...