Using `CFT` depict the electronic configuration of the rhodium ion `(Rh^(2+))` in an octahedral field for which the crystal field splitting `Delta_(0)` is greater than the pairing eneryg `P`
(b) Calculate the crystal field stabilisation energy for this configuration (in terms of Delta andP)` .

Explanation

To solve the problem step by step, we will follow the guidelines of Crystal Field Theory (CFT) and apply it to the rhodium ion \( \text{Rh}^{2+} \) in an octahedral field.

### Step 1: Determine the Electronic Configuration of Rhodium
- The atomic number of rhodium (Rh) is 45.
- The ground state electronic configuration of Rh is:
\[ \text{[Kr]} \, 4d^8 \, 5s^1 \]
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