Find out the number of unpaired electrons in strong and weak octahedral for `Cr^(3+)` and `Fe^(2+)` ions .

Explanation

To find the number of unpaired electrons in the strong and weak octahedral fields for `Cr^(3+)` and `Fe^(2+)` ions, we can follow these steps:

### Step 1: Determine the electronic configuration of `Cr^(3+)`
- The atomic number of Chromium (Cr) is 24. Its electronic configuration is:
- Ground state: `1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁵ 4s¹`
- For `Cr^(3+)`, we remove three electrons. The first two electrons are removed from the 4s orbital and one from the 3d orbital:
- `Cr^(3+)`: `3d³`

...