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According to crystal field theory the el...

According to crystal field theory the electronic configuration of the compound `[Mn(CN)_(4)]^(2-)` is `(DeltagtP)` :

A

`4(e^(4)t_(2)^(1))`

B

`(e^(2) t_(2)^(3))`

C

`4(e^(2)t_(2)^(3))`

D

`3(e^(4).t_(2)^(1))` .

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The correct Answer is:
To determine the electronic configuration of the manganese ion in the complex \([Mn(CN)_{4}]^{2-}\) according to crystal field theory, we will follow these steps: ### Step 1: Determine the oxidation state of manganese (Mn) 1. The overall charge of the complex is \(-2\). 2. Each cyanide ligand (CN) has a charge of \(-1\). Since there are 4 cyanide ligands, their total contribution is \(-4\). 3. Let the oxidation state of Mn be \(x\). Therefore, we have: \[ x + 4(-1) = -2 \] Simplifying this gives: \[ x - 4 = -2 \implies x = +2 \] Thus, the oxidation state of Mn in \([Mn(CN)_{4}]^{2-}\) is \(+2\). ### Step 2: Write the electronic configuration of Mn in its elemental state 1. The atomic number of manganese (Mn) is 25. 2. The electronic configuration of neutral manganese is: \[ [Ar] 3d^5 4s^2 \] ### Step 3: Determine the electronic configuration of Mn in the +2 oxidation state 1. When manganese loses two electrons to form \(Mn^{2+}\), it loses the two 4s electrons first: \[ Mn^{2+}: [Ar] 3d^5 \] ### Step 4: Identify the type of ligands and their effect on electron pairing 1. Cyanide (CN\(^-\)) is a strong field ligand. 2. Strong field ligands cause a large crystal field splitting energy (\(\Delta\)) and favor pairing of electrons in the lower energy orbitals (t2g). ### Step 5: Apply crystal field theory to fill the d-orbitals 1. According to crystal field theory, the \(d\) orbitals split into two sets: \(t_{2g}\) (lower energy) and \(e_g\) (higher energy). 2. For \(Mn^{2+}\) with a \(3d^5\) configuration and a strong field ligand, we fill the orbitals to maximize pairing: - Fill the \(t_{2g}\) orbitals first before moving to \(e_g\). - Since we have 5 electrons, they will fill as follows: - \(t_{2g}\): 5 electrons (fully filled) - \(e_g\): 0 electrons ### Final Electronic Configuration Thus, the electronic configuration of \(Mn^{2+}\) in the complex \([Mn(CN)_{4}]^{2-}\) is: \[ t_{2g}^5 \, e_g^0 \] ---

To determine the electronic configuration of the manganese ion in the complex \([Mn(CN)_{4}]^{2-}\) according to crystal field theory, we will follow these steps: ### Step 1: Determine the oxidation state of manganese (Mn) 1. The overall charge of the complex is \(-2\). 2. Each cyanide ligand (CN) has a charge of \(-1\). Since there are 4 cyanide ligands, their total contribution is \(-4\). 3. Let the oxidation state of Mn be \(x\). Therefore, we have: \[ x + 4(-1) = -2 ...
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