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Crystal field splitting energy (CFSE) fo...

Crystal field splitting energy `(CFSE)` for the complex `[Cr(NH_(3))_(6)]^(2+)` is when ` P =125` and `Delta_(0) =250kjmol^(-1)` .

A

`525kJmo1^(-1)`

B

`275kJmo1^(-1)`

C

`-275kJmo1^(-1)`

D

`-525kJm01^(1-)`

Text Solution

Verified by Experts

The correct Answer is:
c
`Delta gtP` strong field, pairing low spin
Octahedral complex `CN =6`
`Cr = 3d^(5) 4s^(1) ,Cr^(+2) = 3d^(4)` ,Structure 3 `(t_(2g)^4e_(g)0)`
`CFSE = (-0.4 xx 4)Delta_(0) + P = - 1.6 xx 250 + 125`
` =- 275 kJ mo1^(-1)` .
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