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In which structure crystal field splitti...

In which structure crystal field splitting energey `(CFSE)` for octahedral complex will be zero when `DeltaltP` .

A

`d^(5)`

B

`d^(6)`

C

`d^(8)`

D

`d^(10)`

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The correct Answer is:
To solve the question regarding the crystal field splitting energy (CFSE) for octahedral complexes when Δ < P, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Terms**: - **Crystal Field Splitting Energy (CFSE)**: This is the energy difference between the split d-orbitals in a crystal field. - **Δ (Delta)**: Represents the crystal field splitting energy. - **P (Pairing Energy)**: The energy required to pair up electrons in the same orbital. 2. **Identifying the Condition**: - The condition given is Δ < P, which indicates a weak field ligand scenario. In this case, the pairing of electrons is less favorable, leading to high spin complexes. 3. **Electron Configuration in Octahedral Complex**: - In an octahedral field, the d-orbitals split into two sets: - **T2g (lower energy)**: Contains three orbitals. - **Eg (higher energy)**: Contains two orbitals. 4. **Filling the d-Orbitals**: - For a high spin complex (where Δ < P), electrons will occupy the T2g and Eg orbitals without pairing until all orbitals are singly occupied. - For example, in a d5 configuration, the electrons will fill as follows: - T2g: 3 electrons (one in each orbital) - Eg: 2 electrons (one in each orbital) 5. **Calculating CFSE**: - The CFSE can be calculated using the formula: \[ \text{CFSE} = (n_{T2g} \times -0.4 \Delta) + (n_{Eg} \times 0.6 \Delta) \] - For a d5 configuration: - \( n_{T2g} = 3 \) and \( n_{Eg} = 2 \) - CFSE = \( (3 \times -0.4 \Delta) + (2 \times 0.6 \Delta) \) - CFSE = \( -1.2 \Delta + 1.2 \Delta = 0 \) 6. **Conclusion**: - The CFSE for a d5 configuration in an octahedral complex is zero when Δ < P. Similarly, for a d10 configuration, all orbitals are fully filled, leading to a similar CFSE of zero. - Therefore, the structures where CFSE is zero under the condition Δ < P are d5 and d10 configurations. ### Final Answer: The CFSE for octahedral complexes will be zero for d5 and d10 configurations when Δ < P. ---

To solve the question regarding the crystal field splitting energy (CFSE) for octahedral complexes when Δ < P, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Terms**: - **Crystal Field Splitting Energy (CFSE)**: This is the energy difference between the split d-orbitals in a crystal field. - **Δ (Delta)**: Represents the crystal field splitting energy. - **P (Pairing Energy)**: The energy required to pair up electrons in the same orbital. ...
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