Consider the following experiments and answer the questions at the end of it
(A) When `Fe(CN)_(2)` solution is treated with `KCN` solution species formed no longer gives tests of `Fe^(2+)` and `CN^(Θ)`
(B) When `K_(2)SO_(4)` solution is treated with `A1_(2)(SO_(4))_(3)` solution species formed gives tests of `K^(o+),A1^(3+)` and `SO_(4)^(2-)`
Species formed in experiment `(B)` is .

Options

A. Complex
B. Double salt
C. Liquid crystal
D. None of these

Explanation

To solve the question regarding the species formed in experiment (B), we can follow these steps:

### Step 1: Identify the reactants in experiment (B)
In experiment (B), we have two reactants: `K2SO4` (potassium sulfate) and `Al2(SO4)3` (aluminum sulfate).

### Step 2: Understand the nature of the reaction
When `K2SO4` is mixed with `Al2(SO4)3`, they can form a double salt. Double salts are formed when two different salts crystallize together from a saturated solution.

### Step 3: Determine the species formed
The double salt formed from the reaction of `K2SO4` and `Al2(SO4)3` is known as potash alum. The formula for potash alum is `KAl(SO4)2·12H2O`.

### Step 4: Analyze the tests for ions
The question states that the species formed gives tests for `K^+`, `Al^3+`, and `SO4^2-`. This indicates that the potash alum contains potassium ions, aluminum ions, and sulfate ions.

### Conclusion
Thus, the species formed in experiment (B) is potash alum, which can be represented as `KAl(SO4)2·12H2O`.

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