In the manufacture of iron a gas `(A)` is formed in the zone of combustion of the blast furnace The gad `(A)` formed in the zone of combustion of the blast furnace. The gas `(A)` reacted with coke in the zone of fusion to from another gas `(B).X` moles of `(B)` reacts with iron at `200^(@)C` and `100` atm pressure to form a compounds `(C)` will be
The magnetic moment and effective atomic number of the `C` repectively, are
(a) `4.93` and `36`
(b) `0` and `34`
(c ) ``0` and `36`
(d) None .

Explanation

To solve the given problem step by step, we will analyze the information provided and derive the required values for the magnetic moment and effective atomic number of the compound formed.

### Step 1: Identify the gas (A) formed in the blast furnace
In the manufacture of iron, the gas (A) formed in the combustion zone of the blast furnace is carbon dioxide (CO₂).

**Hint:** Think about the combustion process in a blast furnace and the typical gases produced.

### Step 2: Determine the reaction of gas (A) with coke
The gas (A), which is CO₂, reacts with coke (carbon) to form carbon monoxide (CO):
\[ \text{CO}_2 + \text{C} \rightarrow 2 \text{CO} \]

**Hint:** Recall that coke is primarily carbon and can reduce CO₂ to CO.

### Step 3: Identify the reaction of gas (B) with iron
The gas (B) formed is carbon monoxide (CO). This gas reacts with iron (Fe) to form a compound, which is iron pentacarbonyl (Fe(CO)₅):
\[ \text{Fe} + 5 \text{CO} \rightarrow \text{Fe(CO)}_5 \]

**Hint:** Consider the coordination chemistry of transition metals with carbon monoxide as ligands.

### Step 4: Determine the electronic configuration of iron
Iron (Fe) has an atomic number of 26. Its electronic configuration is:
\[ \text{Fe: } [\text{Ar}] 3d^6 4s^2 \]

**Hint:** Remember the order of filling of orbitals and the atomic number of iron.

### Step 5: Analyze the effect of CO as a strong field ligand
In the presence of a strong field ligand like CO, the electrons in the d-orbitals will pair up. For Fe in Fe(CO)₅:
- The 3d electrons will pair up, resulting in the configuration: \( (3d)^{6} \) becomes \( (3d)^{6} \) with all paired electrons.

**Hint:** Strong field ligands cause pairing of electrons in the d-orbitals.

### Step 6: Calculate the magnetic moment
The formula for magnetic moment (μ) is given by:
\[ \mu = \sqrt{n(n + 2)} \]
where \( n \) is the number of unpaired electrons. Since all electrons are paired in Fe(CO)₅, \( n = 0 \):
\[ \mu = \sqrt{0(0 + 2)} = 0 \]

**Hint:** Remember that unpaired electrons contribute to the magnetic moment.

### Step 7: Calculate the effective atomic number (EAN)
The effective atomic number (EAN) is calculated using the formula:
\[ \text{EAN} = Z + n \]
where \( Z \) is the atomic number of the metal (Fe) and \( n \) is the number of electrons donated by the ligands. In this case, CO donates 2 electrons each, and there are 5 CO ligands:
\[ \text{EAN} = 26 + 5 \times 2 = 26 + 10 = 36 \]

**Hint:** Consider the contribution of each ligand to the total electron count.

### Conclusion
The magnetic moment of compound (C) is 0, and the effective atomic number is 36. Therefore, the correct answer is:
**(c) 0 and 36.**