Select the correct `IUPA` name for `[Cr(C_(6)H_(6))(CO)_(3)]` .

Options

A. `(eta^(6)`benzene) tricarbonylchromate(0)
B. Tricarbony1`(eta^(6)`benzene) tricarbonylchromate(0)
C. Tricarbony1`(eta^(6)`benzene) tricarbonylchromium(0)
D. `(eta^(6)`benzene) tricarbonylchromium(0)

Answer

To determine the correct IUPAC name for the complex \([Cr(C_6H_6)(CO)_3]\), we will follow the systematic approach for naming coordination compounds.

### Step-by-Step Solution:

1. **Identify the Ligands**:
- The complex contains two types of ligands:
- \(C_6H_6\) (benzene)
- \(CO\) (carbonyl)

2. **Determine the Hapticity of Ligands**:
- Benzene (\(C_6H_6\)) acts as a ligand with a hapticity of 6, denoted as \(\eta^6\).
- Carbonyl (\(CO\)) is a neutral ligand and does not have a specific hapticity notation since it binds through a single atom.

3. **Count the Number of Each Ligand**:
- There is one benzene ligand and three carbonyl ligands.

4. **Alphabetical Order of Ligands**:
- When naming ligands, they must be listed in alphabetical order.
- The alphabetical order is based on the name of the ligand, not the prefixes (like di-, tri-).
- Therefore, we will list "benzene" first (as \(\eta^6\) benzene) and then "carbonyl" (as tricarbonyl).

5. **Determine the Metal and Its Oxidation State**:
- The metal in the complex is chromium (Cr).
- To find the oxidation state of chromium, we set up the equation:
- Let the oxidation state of chromium be \(X\).
- The ligands (benzene and carbonyl) are neutral, contributing 0 to the charge.
- Therefore, the overall charge of the coordination sphere is 0.
- Thus, \(X + 0 + 0 = 0\) leads to \(X = 0\).
- The oxidation state of chromium is 0.

6. **Construct the IUPAC Name**:
- Combine the names of the ligands and the metal with the oxidation state.
- The correct IUPAC name will be: \(\eta^6\) benzene tricarbonyl chromium(0).

### Final Answer:
The correct IUPAC name for the complex \([Cr(C_6H_6)(CO)_3]\) is **\(\eta^6\) benzene tricarbonyl chromium(0)**.