The compound `[CoCI_(3)I(C_(5)H_(5)N)_(2)]` Br will show the chemical test for which of the following ions? .

Options

A. `Br^(Θ)`
B. `CI^(Θ)`
C. `I^(Θ)`
D. `Br^(Θ)` as well as `CI^(Θ)`

Answer

To solve the question regarding the compound `[CoCl_(3)I(C_(5)H_(5)N)_(2)] Br`, we need to identify which ions this compound can be tested for. Here’s a step-by-step breakdown of the solution:

### Step 1: Analyze the Compound
The given compound is `[CoCl_(3)I(C_(5)H_(5)N)_(2)] Br`. This compound consists of:
- A cobalt (Co) ion as the central metal.
- Three chloride ions (Cl).
- One iodide ion (I).
- Two pyridine molecules (C₅H₅N) as ligands.
- One bromide ion (Br) as the anionic part.

### Step 2: Identify the Coordination Sphere
In coordination compounds, the coordination sphere consists of the central metal ion and the ligands attached to it. In this case, the coordination sphere is `[CoCl_(3)I(C_(5)H_(5)N)_(2)]`, while the bromide ion (Br) is outside the coordination sphere.

### Step 3: Ionization of the Compound
When the compound dissociates in solution, it will break down into its constituent ions. The dissociation can be represented as:
\[ [CoCl_{3}I(C_{5}H_{5}N)_{2}]^{+} + Br^{-} \rightarrow Co^{3+} + 3Cl^{-} + I^{-} + 2C_{5}H_{5}N + Br^{-} \]

### Step 4: Identify the Available Ions
From the dissociation, we can see that the ions present in the solution are:
- Cobalt ion (Co³⁺)
- Chloride ions (Cl⁻)
- Iodide ion (I⁻)
- Pyridine molecules (C₅H₅N)
- Bromide ion (Br⁻)

### Step 5: Conduct a Chemical Test
To identify the presence of bromide ions (Br⁻), we can perform a chemical test using silver nitrate (AgNO₃). When silver nitrate is added to the solution containing bromide ions, a white precipitate of silver bromide (AgBr) will form:
\[ Br^{-} + AgNO_{3} \rightarrow AgBr (s) + NO_{3}^{-} \]

### Conclusion
The compound `[CoCl_(3)I(C_(5)H_(5)N)_(2)] Br` will show a chemical test for bromide ions (Br⁻) when treated with silver nitrate.

### Final Answer
**Option A: Bromide ions (Br⁻)**

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