The correct `IUPA` name of `[AICI_(3)].4(EtOH)` is .

Options

A. Aluminium(II) chloride-4-ethanol
B. Trichloridoaluminium(III)-4-ethaol
C. Aluminium(III)chloride-4-hydroxyethane
D. Aluminium chloride-4-ethanol

Answer

To determine the correct IUPAC name of the compound \([AlCl_3] \cdot 4(EtOH)\), we will follow these steps:

### Step 1: Identify the Components
The compound consists of:
- Aluminium chloride \((AlCl_3)\)
- Ethanol \((EtOH)\) as a ligand, with 4 molecules present.

### Step 2: Determine the Oxidation State of Aluminium
In \([AlCl_3]\):
- Let the oxidation state of Aluminium be \(x\).
- The oxidation state of each chloride ion is \(-1\).
- Since there are 3 chloride ions, the total contribution from chlorine is \(-3\).
- The overall charge of the coordination sphere is assumed to be 0.

Setting up the equation:
\[ x + (-3) = 0 \implies x = +3 \]
Thus, the oxidation state of Aluminium is +3.

### Step 3: Naming the Ligands
The ligands in this compound are chloride ions and ethanol.
- The name for the ligand derived from chloride is "chlorido".
- Since there are 3 chloride ions, we use the prefix "tri-", resulting in "trichlorido".

### Step 4: Naming the Central Metal Atom
The central metal atom is Aluminium, which we name as "aluminium". Since it has an oxidation state of +3, we denote this in the name as "aluminium(III)".

### Step 5: Naming the Ethanol Ligands
Ethanol is denoted as "ethanol" in the IUPAC nomenclature. Since there are 4 ethanol molecules, we prefix it with "tetra-", resulting in "tetraethanol".

### Step 6: Combine All Parts
Now we combine all parts to form the complete IUPAC name:
- Ligands: "trichlorido" for the chlorides and "tetraethanol" for the ethanol.
- Central metal: "aluminium(III)".

Thus, the final IUPAC name is:
\[ \text{trichloridoaluminium(III) tetraethanol} \]

### Final Answer
The correct IUPAC name of \([AlCl_3] \cdot 4(EtOH)\) is:
**trichloridoaluminium(III) tetraethanol**

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