Geometry, hybridisation and magnetic moment of the ions `[Ni(CN)_(4)]^(2-),[MnBr_(4)]^(2-)` and `[FeF_(6)]^(3-)` respectively are .

Options

A. Tetrahedral square planar,octahedral `dsp^(2),sp^(3),sp^(3):0,5.9,4.9` .
B. Tetrahedral square planar,octahedral `sp^(3),dsp^(2),sp^(3)d^(2):5.9,0,4,9` .
C. Square planar,tetrahedral,octahedral: `dsp^(2),sp^(3),d^(2)sp^(3):5.9,4.9,0` .
D. Tetrahedral square planar,octahedral `dsp^(2),sp^(3),sp^(3)d^(2):0,5,4.9` .

Answer

To determine the geometry, hybridization, and magnetic moment of the coordination compounds `[Ni(CN)₄]²⁻`, `[MnBr₄]²⁻`, and `[FeF₆]³⁻`, we can follow these steps:

### Step 1: Analyze `[Ni(CN)₄]²⁻`
1. **Oxidation State**: Nickel (Ni) in `[Ni(CN)₄]²⁻` has an oxidation state of +2.
2. **Electron Configuration**: The electron configuration of Ni is [Ar] 3d⁸ 4s². For Ni²⁺, it becomes 3d⁸.
3. **Ligand Field**: CN⁻ is a strong field ligand, which causes pairing of electrons in the d-orbitals.
4. **Hybridization**: The coordination number is 4, and with strong field ligands, the hybridization is dsp².
5. **Geometry**: The geometry of dsp² hybridization is square planar.
6. **Magnetic Moment**: Since all electrons are paired, the magnetic moment is 0 BM.

### Step 2: Analyze `[MnBr₄]²⁻`
1. **Oxidation State**: Manganese (Mn) in `[MnBr₄]²⁻` has an oxidation state of +2.
2. **Electron Configuration**: The electron configuration of Mn is [Ar] 3d⁵ 4s². For Mn²⁺, it becomes 3d⁵.
3. **Ligand Field**: Br⁻ is a weak field ligand, which does not cause pairing of electrons.
4. **Hybridization**: The coordination number is 4, and with weak field ligands, the hybridization is sp³.
5. **Geometry**: The geometry of sp³ hybridization is tetrahedral.
6. **Magnetic Moment**: There are 5 unpaired electrons, so the magnetic moment is calculated as √(n(n+2)) = √(5(5+2)) = √35 ≈ 5.92 BM.

### Step 3: Analyze `[FeF₆]³⁻`
1. **Oxidation State**: Iron (Fe) in `[FeF₆]³⁻` has an oxidation state of +3.
2. **Electron Configuration**: The electron configuration of Fe is [Ar] 3d⁶ 4s². For Fe³⁺, it becomes 3d⁵.
3. **Ligand Field**: F⁻ is a weak field ligand, which does not cause pairing of electrons.
4. **Hybridization**: The coordination number is 6, and with weak field ligands, the hybridization is sp³d².
5. **Geometry**: The geometry of sp³d² hybridization is octahedral.
6. **Magnetic Moment**: There are 5 unpaired electrons, so the magnetic moment is calculated as √(n(n+2)) = √(5(5+2)) = √35 ≈ 5.92 BM.

### Summary of Results
- **[Ni(CN)₄]²⁻**:
- Geometry: Square planar
- Hybridization: dsp²
- Magnetic Moment: 0 BM

- **[MnBr₄]²⁻**:
- Geometry: Tetrahedral
- Hybridization: sp³
- Magnetic Moment: 5.92 BM

- **[FeF₆]³⁻**:
- Geometry: Octahedral
- Hybridization: sp³d²
- Magnetic Moment: 5.92 BM