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[Cr(H(2)O)(6)]Cl(3) (at no. of Cr = 24) ...

`[Cr(H_(2)O)_(6)]Cl_(3)` (at no. of Cr = 24) has a magnetic moment of 3.83 B.M . The correct distribution of 3d electrons in the chromium present in the complex is

A

`3d_(xy)^(1),3d_(yz)^(1),3d_(zx)^(1)`

B

`3d_(xy)^(1),3d_(yz)^(1),3d_(z2)^(1)`

C

`3d_((x^(2)-y^(2)))^(1)3d_(z^(2))^(1),3d_(xz)^(1)`

D

`3d_(xy)^(1),3d_((x^(2)-y^(2)))^(1),3d^(1)xz`

Text Solution

Verified by Experts

The correct Answer is:
A
magnetic momnet indicates that there are three unpaired electrons present in chromium These must be present in lower energy orbitals which are `3d_(xy) 3d_(yx)` and `3d_(xz)` .
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