`Ag^(o+)` forms complexes some of these are
`[Ag(NH_(3))_(2)]^(o+),2[Ag(CN)_(2)]^(Θ),[Ag(S_(2)O_(3))_(2)]^(3-)`
Which of the following statements is true? .

Options

A. In these complexes, `Ag^(o+)` is a Lewis bese .
B. The hybrisation `Ag^(o+)` is `sp^(2)` .
C. The `Ag^(o+)` complexes are good reducing agents.
D. These complexes are all linear .

Answer

To solve the question regarding the complexes formed by Ag^+ and determine which statement is true, we can follow these steps:

### Step 1: Identify the nature of Ag^+
Ag^+ is a transition metal cation that can act as a Lewis acid. This means it can accept electron pairs from ligands.

**Hint:** Remember that Lewis acids accept electrons, while Lewis bases donate electrons.

### Step 2: Analyze the coordination number
In the given complexes, we see that Ag^+ forms complexes with different ligands. The coordination number for Ag^+ in these complexes is typically 2, as it can form two bonds with ligands.

**Hint:** Coordination number is determined by the number of ligand atoms that are directly bonded to the central metal atom.

### Step 3: Determine the hybridization
Since Ag^+ has a coordination number of 2, the hybridization is sp. This results in a linear geometry for the complexes.

**Hint:** The hybridization can be determined from the coordination number: 2 corresponds to sp hybridization.

### Step 4: Evaluate the stability of the complexes
The complexes formed by Ag^+ are stable due to its electronic configuration. As a d10 metal, it is stable and does not easily undergo oxidation.

**Hint:** Stability of complexes can often be related to the electron configuration of the metal ion.

### Step 5: Analyze the options
Now, we can evaluate the statements provided in the question:
1. Ag^+ is a Lewis base - **False** (Ag^+ is a Lewis acid)
2. The hybridization of Ag^+ is sp2 - **False** (It is sp)
3. The Ag^+ complexes are good reducing agents - **False** (They are stable and not good reducing agents)
4. All complexes are linear due to sp hybridization - **True** (This is correct)

### Conclusion
The correct statement is that all complexes formed by Ag^+ are linear due to its sp hybridization.

**Final Answer:** The correct statement is: "All complexes are linear due to sp hybridization."

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