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Delta(0) increases in the order of [CrCI...

`Delta_(0)` increases in the order of `[CrCI_(6)]^(3-)lt[Cr(CN)_(6)]^(3-)lt[Cr(C_(2)O_(4))_(3)]^(3-)`
reason The stronger the ligand field the higher will be `Delta_(0)` value .

A

If both `(A)` and ` (R )` are correct and `(R )` is the correct explanation of `(A ) ` .

B

If both `(A)` and ` (R )` are correct and `(R )` is the correct explanation of `(A ) ` .

C

If`(A)` is correct, but `( R )` is incorrect .

D

Both `(A)` and `(R ) ` are incorrect .

Text Solution

Verified by Experts

The correct Answer is:
D
Accoring to spectrochemical series `CN^(Θ)` is a strong field ligands, so it has more `Delta_(0)` for these complex ions is
`[CrCI_(6)]^(3-)lt[Cr(C_(2)O_(4))_(3)]^(2-)lt[Cr(CN)_(6)]^(3-)` .
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The degenerate orbitals of [Cr(H_(2)O)_(6)]^(3+) are:

When degenerate d-orbitals of an isolated atom/ion come under influence of magnetic field of ligands, the degeneray is lost. The two set t_(2g)(d_(xy),d_(yz),d_(xz)) and e_(g) (d_(x^(2))-d_(x^(2)-y^(2)) are either stabilized or destabilized depending upon the nature of magnetic field. it can be expressed diagrammatically as: Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally, for tetrahedral complexes, Delta is about 4/9 times to Delta_(0) (CFSE for octahedral complex). this energy lies in visible region and i.e., why electronic transition are responsible for colour. such transition are not possible with d^(0) and d^(10) configuration. Q. Cr^(3+) form four complexes with four different ligands which are [Cr(Cl)_(6)]^(3-), [Cr(H_(2)O)_(6)]^(3+) , [Cr(NH_(3))_(6)]^(3+) and [Cr(CN)_(6)]^(3-) , the order of CFSE (Delta_(0)) in these complexes in the order:

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