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Write the sum of geometrical isomers in ...

Write the sum of geometrical isomers in `[Ma_(2)b_(2)c_(2)]` complex and stereoisomers in `[M(AB)_(3)]` complex .

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To solve the question regarding the sum of geometrical isomers in the complex \([Ma_2b_2c_2]\) and stereoisomers in the complex \([M(AB)_3]\), we will break it down into two parts. ### Step 1: Determine the geometrical isomers of \([Ma_2b_2c_2]\) 1. **Identify the ligands**: We have three different monodentate ligands: A, B, and C. 2. **Count the possible arrangements**: - **Cis Isomers**: - One possible arrangement is where all A's are adjacent (cis), and B's and C's can also be adjacent. This gives us the first isomer: **AA, BB, CC** (cis). - **Trans Isomers**: - The second arrangement can have A's in trans positions, while B's and C's are in cis positions. This gives us the second isomer. - We can also have B's in cis and A's and C's in trans, giving us the third isomer. - Another arrangement can have C's in cis and A's and B's in trans, giving us the fourth isomer. - **All Trans Isomer**: - Finally, we can have all ligands in trans positions, giving us the fifth isomer. 3. **Total geometrical isomers**: After considering all arrangements, we find that there are a total of **5 geometrical isomers**. ### Step 2: Determine the stereoisomers of \([M(AB)_3]\) 1. **Identify the ligand**: Here, AB is a bidentate ligand, meaning it can attach to the metal at two points. 2. **Count the possible arrangements**: - The complex can exist in both **cis** and **trans** forms. - Each of these forms can also exhibit optical activity because the arrangement of the bidentate ligands can create non-superimposable mirror images. 3. **Total stereoisomers**: - There are **2 forms (cis and trans)**, and since both can be optically active, we multiply by 2, giving us a total of **4 stereoisomers**. ### Final Calculation Now, we sum the geometrical isomers and stereoisomers: - Geometrical isomers: 5 - Stereoisomers: 4 Thus, the total sum is: \[ 5 + 4 = 9 \] ### Final Answer The sum of geometrical isomers in \([Ma_2b_2c_2]\) and stereoisomers in \([M(AB)_3]\) is **9**.

To solve the question regarding the sum of geometrical isomers in the complex \([Ma_2b_2c_2]\) and stereoisomers in the complex \([M(AB)_3]\), we will break it down into two parts. ### Step 1: Determine the geometrical isomers of \([Ma_2b_2c_2]\) 1. **Identify the ligands**: We have three different monodentate ligands: A, B, and C. 2. **Count the possible arrangements**: - **Cis Isomers**: - One possible arrangement is where all A's are adjacent (cis), and B's and C's can also be adjacent. This gives us the first isomer: **AA, BB, CC** (cis). ...
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