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Give the number of geometrical isomers i...

Give the number of geometrical isomers in `[Pt(gly)_(2)]` .

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To determine the number of geometrical isomers for the complex `[Pt(gly)_(2)]`, where gly is the glycinato ligand, we can follow these steps: ### Step 1: Identify the Coordination Number and Geometry The complex `[Pt(gly)_(2)]` has a platinum (Pt) center coordinated to two glycinato ligands. Glycinato is a bidentate ligand, meaning each glycinato can bind to the platinum at two sites. Therefore, the coordination number of platinum in this complex is 4. **Hint:** Remember that bidentate ligands can attach to the central metal atom at two different points. ### Step 2: Determine the Geometry of the Complex With a coordination number of 4, the geometry of the complex is square planar. This is a common geometry for d8 metal complexes, such as those of platinum. **Hint:** Square planar geometry is typical for transition metals with a coordination number of 4. ### Step 3: Analyze the Ligand Arrangement In a square planar complex, the arrangement of the ligands can lead to different spatial configurations. The two glycinato ligands can either be adjacent to each other (cis configuration) or opposite each other (trans configuration). **Hint:** Visualize the square planar arrangement and consider how the ligands can be positioned relative to each other. ### Step 4: Identify the Geometrical Isomers 1. **Cis Isomer:** In the cis configuration, the two glycinato ligands are adjacent to each other. This means that the donor atoms (N and O) from the two ligands are positioned next to each other in the square plane. 2. **Trans Isomer:** In the trans configuration, the two glycinato ligands are opposite each other. This means that the donor atoms from one ligand are positioned opposite to the donor atoms of the other ligand. **Hint:** Draw the structures for both the cis and trans isomers to visualize the differences. ### Step 5: Count the Geometrical Isomers Since we have identified two distinct arrangements (cis and trans), the total number of geometrical isomers for the complex `[Pt(gly)_(2)]` is 2. **Final Answer:** The number of geometrical isomers in `[Pt(gly)_(2)]` is 2.
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