Give the total number of possible structural isomers of the compound `overset(II)[(Cu(NH_(3))_(4)][overset(II)(Pt Cl_(4))]` .

Explanation

To determine the total number of possible structural isomers of the compound \([Cu(NH_3)_4][PtCl_4]\), we will analyze the coordination complexes formed by copper and platinum. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Coordination Complexes
The given compound consists of two coordination complexes:
1. Copper complex: \([Cu(NH_3)_4]^{2+}\)
2. Platinum complex: \([PtCl_4]^{2-}\)

### Step 2: Determine the Oxidation States
- Copper (Cu) is in the +2 oxidation state.
- Platinum (Pt) is also in the +2 oxidation state.

### Step 3: Understand the Coordination Numbers
- The coordination number for both copper and platinum is 4, which means each metal ion is surrounded by four ligands.

### Step 4: Identify Possible Structural Isomers
Structural isomers can arise from different arrangements of ligands around the metal centers. The following structural isomers can be formed:

1. **Isomer 1**: \([Cu(NH_3)_4][PtCl_4]\)
- Copper is coordinated to four ammonia ligands, and platinum is coordinated to four chloride ligands.

2. **Isomer 2**: \([Cu(NH_3)_3Cl][PtCl_3(NH_3)]\)
- One ammonia ligand is transferred from copper to platinum, resulting in three ammonia and one chloride around copper, and three chlorides and one ammonia around platinum.

3. **Isomer 3**: \([Cu(NH_3)_2Cl_2][PtCl_2(NH_3)_2]\)
- Two ammonia ligands are transferred from copper to platinum, resulting in two ammonia and two chlorides around copper, and two chlorides and two ammonia around platinum.

4. **Isomer 4**: \([Cu(NH_3)Cl_3][PtCl(NH_3)_3]\)
- Three ammonia ligands are transferred from copper to platinum, resulting in one ammonia and three chlorides around copper, and one chloride and three ammonia around platinum.

5. **Isomer 5**: \([CuCl_4][Pt(NH_3)_4]\)
- All ammonia ligands are transferred to platinum, resulting in four chlorides around copper and four ammonia around platinum.

### Step 5: Count the Isomers
From the analysis, we can see that there are a total of **five possible structural isomers** for the compound \([Cu(NH_3)_4][PtCl_4]\).

### Final Answer
The total number of possible structural isomers of the compound \([Cu(NH_3)_4][PtCl_4]\) is **5**.

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