How many maximum atom (s)is//are are present in same plane of `Cr(CO)_(6)` ? .

Explanation

To determine the maximum number of atoms present in the same plane of the coordination compound `Cr(CO)_(6)`, we can follow these steps:

### Step 1: Understand the Structure of `Cr(CO)_(6)`
`Cr(CO)_(6)` is a coordination complex where chromium (Cr) is the central metal atom and carbon monoxide (CO) acts as a ligand. There are six CO ligands coordinated to the chromium.

### Step 2: Identify the Geometry
The geometry of `Cr(CO)_(6)` is octahedral. In an octahedral arrangement, the ligands are positioned at the corners of an octahedron around the central metal atom.

### Step 3: Determine the Position of Atoms
In an octahedral complex:
- Four of the CO ligands will lie in the same plane (the equatorial plane).
- The remaining two CO ligands will be positioned above and below this plane (the axial positions).

### Step 4: Count the Atoms in the Same Plane
In the equatorial plane, we have:
- 4 carbon atoms from the 4 CO ligands.
- 4 oxygen atoms from the 4 CO ligands.
- 1 chromium atom at the center.

Thus, the total number of atoms in the same plane is:
- 4 (C) + 4 (O) + 1 (Cr) = 9 atoms.

### Conclusion
The maximum number of atoms present in the same plane of `Cr(CO)_(6)` is **9**.

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