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d^(2) sp^(3) hybridisation of the centra...

`d^(2) sp^(3)` hybridisation of the central atom gives the ______orbital complex while `sp^(3) d^(2)` hybridisation gives the_________orbital complex .

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To solve the question regarding the hybridization of the central atom and the type of orbital complex formed, we will analyze the two types of hybridization mentioned: \(d^2sp^3\) and \(sp^3d^2\). ### Step 1: Understanding \(d^2sp^3\) Hybridization - In \(d^2sp^3\) hybridization, the d orbitals involved are from the (n-1) shell, while the s and p orbitals are from the n shell. - For example, if we consider the central atom in the 4th period, the involved orbitals would be 3d (from the n-1 shell), 4s, and 4p (from the n shell). - This type of hybridization leads to the formation of an **inner orbital complex**. ### Step 2: Understanding \(sp^3d^2\) Hybridization - In \(sp^3d^2\) hybridization, all the orbitals (s, p, and d) are from the same shell, which is the n shell. - Using the same example of the 4th period, the involved orbitals would be 4s, 4p, and 4d. - This hybridization results in the formation of an **outer orbital complex**. ### Conclusion - Therefore, the answer to the question is: - \(d^2sp^3\) hybridization of the central atom gives the **inner orbital complex** while \(sp^3d^2\) hybridization gives the **outer orbital complex**.
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CENGAGE CHEMISTRY ENGLISH-COORDINATION COMPOUNDS-Exercises Fill The Blanks
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  2. Organometallic compounds are those compounds which contain one or more...

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  10. According to valence bond theory the geometry of [Ni(CO)(4)] is .

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  11. K(4)Fe(CO)(6) is considered to a be a complex but potash alum isand bl...

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  14. [ptabcd]^(n+-) hasshape and has geometrical isomers .

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  18. EDTA is used as a complexing agent in estimation of metal ions like Ca...

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  19. Potassium hexanitrocobaltate III K(3)[Co(NO(2))(6)] is called .

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