Write true or false: `Fe(CO)_(5)` has trigonal bipyramidal geometry .

Answer

To determine whether the statement "Fe(CO)₅ has trigonal bipyramidal geometry" is true or false, we can follow these steps:

### Step 1: Identify the Compound
The compound in question is Fe(CO)₅, which is known as iron pentacarbonyl.

### Step 2: Determine the Oxidation State of Iron
In Fe(CO)₅, carbon monoxide (CO) is a neutral ligand, meaning it does not contribute any charge. Therefore, the oxidation state of iron (Fe) in this complex is 0.

### Step 3: Analyze the Coordination Number
Iron is coordinated to five CO ligands. The coordination number is the number of ligand atoms that are bonded to the central metal atom. In this case, the coordination number is 5.

### Step 4: Determine the Hybridization
The hybridization of the central metal atom can be determined by the formula:
\[ \text{Hybridization} = \text{Number of Sigma Bonds} + \text{Number of Lone Pairs} \]
Here, Fe forms 5 sigma bonds with the 5 CO ligands and has no lone pairs. Thus, the hybridization is:
\[ \text{Hybridization} = 5 + 0 = 5 \]
This corresponds to sp³d hybridization.

### Step 5: Identify the Geometry
Compounds with sp³d hybridization typically exhibit trigonal bipyramidal geometry. Therefore, since Fe(CO)₅ has sp³d hybridization, its geometry is trigonal bipyramidal.

### Conclusion
Based on the analysis above, the statement "Fe(CO)₅ has trigonal bipyramidal geometry" is **True**.

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