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The coordination number of Ni^(2+) is 4 ...

The coordination number of `Ni^(2+)` is 4
`NiCI_(2) + KCN` (excess)rarr`A` (cyano complex)
Predict the magnetic nature of `A` .

Text Solution

Verified by Experts

The correct Answer is:
b
(i) `[Ni(CN)_(4)]_(2),Ni(Z =28)implies 3d^(8) 4s^(2)`
`Ni^(2+) =3d^(8)`
Cyano is a strong fileld ligand, it causes pairing `dsp^(2)` hybridisation (square planar) There are no unpaired electrons, so the complex is diamagnetic. Spin magnetic moment `=zero`
(ii) `[NiCI_(4)]^(2)`
`Ni^(2+) = [Ar]3d^(8)`
Chlorido is a weak field ligand no pairing `sp^(3)` hybridisation (tetrahedral) Threr are two unpaired electrons, so the complex paramagnetic Spin magnetic moment
`mu =sqrt( n (n +2)) BM = sqrt(2(2 + 2)) BM =sqrt8 BM`
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