The geometry of `Ni(CO)_4` and `Ni(PPh_3)Cl_2` are

Options

A. Both square planar
B. Tetrahedral and square planar,respectively
C. Both tetrahedral
D. Square planar and tetrahedral,respectively

Answer

c

Explanation

(i) `Ni(CO)_(4),Ni(Z =28) =3d^(8)4s^(2)`
`sp^(3)` hybrisation, diamagnetic Geometry of `Ni(CO)_(4)` is tetrahedral
(ii) `Ni(PPh_(3))_(2)CI_(2)`
Oxidation number `=+2`
`Ni^(2+) = 3d^(8)` weak ligand field so no pairing
`sp^(3)` hybridisation and paramagnetic Geometry of `Ni(PPh_(3))_(2)CI_(2)` tetrahedral


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